| J. Goodall, W. Hammond - 1848 - Liczba stron: 390
...circle, a sc alene triangle a rhomboid, and a trapezium. Section 2. 1. Prove that parallelograms upon equal bases and between the same parallels are equal to one another. 2. Describe a parallelogram that shall be equal to a given triangle, and have one of its angles equal... | |
| Euclid, Thomas Tate - 1849 - Liczba stron: 120
...ABC is equal to the triangle DBC. Wherefore triangles, &c. QED PROP. XXXVni. THEOR. Triangles upon equal bases, and between the same parallels, are equal to one another. Let the triangles ABC, DEF be upon equal bases BC, EF, and between the same parallels BF, AD : The... | |
| Great Britain. Committee on Education - 1850 - Liczba stron: 942
...multiple, similar rectilineal figures, and duplicate ratio. 2. Prove Euc. I. 36. Parallelograms upon equal bases, and between the same parallels, are equal to one another. 3. Solve Euc. II. 11. To divide a given finite straight line into two parts, so that the rectangle... | |
| Sir Henry Edward Landor Thuillier - 1851 - Liczba stron: 826
...manner we may prove the parallelogram EFHG = BDEF. Therefore ABDC = BDEF = EFHG. QED Cor. Triangles on the same or equal bases and between the same parallels, are equal, seeing (by Cor. 2. Theo. 11.) they are the halves of their respective parallelograms. THEO. XIII. In... | |
| Harvey Goodwin - 1851 - Liczba stron: 196
...MA, Trinity College. JOHN SYKES, MA, Pembroke College. TUESDAY. Dec. 31. 9. ..12. 1. TRIANGLES upon equal bases and between the same parallels are equal to one another. Let ABC, ABD be two equal triangles upon the same base AB and on opposite sides of it ; join CD meeting... | |
| 1867 - Liczba stron: 336
...vertices of all equal triangles ou the same base and on the same lide of it. 3. Parallelograms upon equal bases, and between the same parallels, are equal to one another. Trisect a parallelogram by lines drawn from a givtu point in one of its sides. SECTION IV. 1. Eqnal... | |
| Francis James Jameson - 1851 - Liczba stron: 144
...CED, two angles are equal and AB = DC, therefore EB - ED. Therefore the triangles BCE, ECD, being upon equal bases and between the same parallels,* are equal to one another. Hence AECD - ABCE - ABEA = AAED. 1851. (A]. Triangles upon equal bases and between the same parallels... | |
| Euclides - 1852 - Liczba stron: 152
...EBCF. Therefore parallelograms upon the same base, &c. QED PROP. XXXVI. THEOR. Parallelograms upon equal bases, and between the same parallels, are equal to one another. Let ABCD, EFGH be parallelograms upon equal bases EC, FG, and between the same parallels AH, EG; the... | |
| Royal Military Academy, Woolwich - 1853 - Liczba stron: 400
...Therefore parallelograms upon the same base, etc. QED PROPOSITION XXXVI. THEOR. Parallelograms upon equal bases, and between the same parallels, are equal to one another. Let ABCD, EFGH be parallelograms upon equal bases BC, FG, and between the same parallels AH, BG : the... | |
| Euclides - 1853 - Liczba stron: 176
...to the triangle dbc. Wherefore triangles, &c. QED PROPOSITION XXXVIII. — THEOREM. Triangles upon equal bases, and between the same parallels, are equal to one another. LET the triangles a bc, def be upon equal bases bc, ef, and between the same parallels bf, ad. Tlle... | |
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