 | Roswell Chamberlain Smith - 1856 - Liczba stron: 334
...then, 25-=-5=5years, the common difference. A. 5 years. 11. Hence, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient Witt te the common difference. 12. If the extremes be 3 and 23, and the number... | |
 | Benjamin Greenleaf - 1857 - Liczba stron: 452
...extremes, 45 — 3 = 42, divided by the number of common differences, 21, gives 2 as the common difference required. RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient will be the common difference. EXAMPLES. 2. A certain school consists of 19 teachers... | |
 | Benjamin Greenleaf - 1857 - Liczba stron: 336
...quotient will be the common difference. Thus, 27 -S- 9 = 3, the common difference. Hence the following RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient is the common difference. EXAMPLES FOR PRACTICE. 1. The extremes of a series are 3... | |
 | James Stewart Eaton - 1857 - Liczba stron: 376
...Hence, 346. PROB. 2. — The extremes and number of terms being given, to find the common difference, RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient will be the common difference. Ex. 1. The extremes of an arithmetical series are 5... | |
 | Charles Guilford Burnham - 1857 - Liczba stron: 328
...238* — When the extremes and number of terms are given, to find the common difference, we have this RULE. Divide the difference of the extremes by the number of terms less 1, and the quotient will be the common difference. 7. If the first term of a series be 3, the last... | |
 | Benjamin Greenleaf - 1858 - Liczba stron: 456
...the number of common differences, 21, gives 2 as the common difference required. RULE. — Dh-itle the difference of the extremes by the number of terms less one, and the quotient will be the common difference. EXAMPLES. 2. A certain school consists of 19 teachers... | |
 | Horatio Nelson Robinson - 1859 - Liczba stron: 348
...one ; thus, by taking away 2 in the fifth term, 2-J-3 + 3 + 3 + 3, we have 3 taken 4 times. Hence, RULE. Divide the difference of the extremes by the number of terms less one. EXAMPLES. 1. The first term is 2, the last term is 17, and the number of terms is 6 ; what is the common... | |
 | Silas Lawrence Loomis - 1859 - Liczba stron: 324
...PROB. CLIII. — GIVEN, THE EXTREMES AND NUMBER OF TERMS, TO FIND THE COMMON DIFFERENCE AND MEANS. RULE Divide the difference of the extremes by the number of terms, less one, for the common difference. Then construct the series by P/ob. CL. PROB. CLIV. — GIVEN, THE EXTREMES... | |
 | Benjamin Greenleaf - 1860 - Liczba stron: 456
...extremes, 45 — 3 = 42, divided by the number of common differences, 21, gives 2 as the common difference required. RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient will be the common difference. EXAMPLES. 2. A certain school consists of 19 teachers... | |
 | Horatio Nelson Robinson - 1860 - Liczba stron: 444
...equal to the common difference multiplied by the number of terms less 1, (706), we have the following RULE. Divide the difference of the extremes by the number of terms less 1. EXAMPLES FOR PRACTICE. 1. If the extremes of an arithmetical series are 3 and 15, and the number... | |
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Hence, when the extremes and number of terms are given, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference. 
