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" The hypothenuse of a right-angled triangle may be found by having the other two sides ; thus, the square root of the sum of the squares of the base and perpendicular, will be the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find the... "
A Treatise of Practical Surveying: Which is Demonstrated from Its First ... - Strona 45
autor: Robert Gibson - 1806 - Liczba stron: 452
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Instructions for the use of the slide-rule, applied to computations relating ...

John EWART (Land Surveyor.) - 1847 - Liczba stron: 83
...of the squares of the other sides ; and either of the sides containing the right angle is equal to the square root of the difference of the squares of the hypothenuse and the other side. Then, to find the hypothenuse of a right-angled triangle from the other sides being...
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A Manual of Surveying for India, Detailing the Mode of Operations on the ...

Ralph Smyth, Sir Henry Edward Landor Thuillier - 1851 - Liczba stron: 718
...of the base and perpendicular, will be the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find the other; the square root of the difference of the squares of the hypothenuse and given side will be the required side. THEO. XIV. In all circles the chord of 60 degrees is always equal in...
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The tutor's assistant

Francis Walkingame - 1855
...top of the wall. Ans. 39-05 fed. fhc hypotfienuse and perpendicular given, to find tlie base. EULE. The square root of the difference of the squares of the hypothenuse and perpendicular is the length of the base. The base and hypotlienuse given, to find the perpendicular....
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Normal Arithmetic: A Text-book, Theoretical and Practical, in Six Parts ...

Silas Lawrence Loomis - 1859 - Liczba stron: 300
...difference of the squares of the Jiypothenuse and base. PROB. CUI. — To FIND THE BASE. RULE. — The square root of the difference of the squares of the hypothenuse and perpendicular. PROB. CIV. — To FIND THE AREA OF A TRIANGLE, THE BASE AND ALTITUDE BEING GIVEN. RULE....
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Walkinghame's [sic] Tutor's assistant; or, Complete arithmetical question ...

Francis Walkingame - 1865
...top of the wall? Ans. 39-05 feet. The hypothenuse and perpendicular given to find the base. RULE. — The square root of the difference of the squares of the hypothenuse and perpendicular is the length of the base. The base and hypothenuse given to find the perpendicular....
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Nelson's Common-school Arithmetic: Designed for the Use of the Lowest as ...

Richard Nelson - 1867 - Liczba stron: 295
...square root of the sum of the squares of the base and perpendicular will give the hypothenuse. And the square root of the difference ,of the squares of the hypothenuse and either of the two sides will give the third side. 22. What length of a ladder will reach across a 15-foot...
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Walkingame's Tutor's assistant, revised and modernized by E. Lethbridge

Francis Walkingame - 1868
...wall. Ans. 29-05 feet, and 975 rem. The Hypoihenuse and Perpendicular given to find the Base. RULE. — The square root of the difference of the squares of the hypothenuse and perpendicular is the length of the base. (8) There is a tower of 103 feet in height, standing close...
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New Practical Arithmetic in which the Science and Its Applications are ...

Henry Bartlett Maglathlin - 1869 - Liczba stron: 324
...the other two sides; and . 3. Hither of the two shorter sides of a right-angled triangle is equal to the square root of the difference of the squares of the hypothenuse and the other side. Exercises. 1. If the base of a right-angled triangle is 60 feet, and the perpendicular...
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Mensuration of lines, surfaces, and volumes

David Munn - 1873
...-AC" 2 (2) = v/(AB +AC)(AB-AC) (3). Interpreting formula (2), we find the remaining side, by taking the square root of the difference of the squares of the hypothenuse and given side. Interpreting formula (3), we find the remaining side, by taking the square root of the product...
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New Practical Arithmetic: In which the Science and Its Applications are ...

Henry Bartlett Maglathlin - 1873 - Liczba stron: 336
...the other two sides; and 3. Either of the two shorter sides of a right-angled triangle is equal to the square root of the difference of the squares of the hypothenuse and the other side. Exercises. 1. If the base of a right-angled triangle is 60 feet, and the perpendicular...
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