A Key to the Exercises and Examples Contained in a Text-book of Euclid's ElementsMacmillan, 1892 - 147 |
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Strona 5
... bisector of A meet BC in X ; then AXC is greater than XAB , that is , than △ XAC ; . ' . AC > CX . AB > BX . and .. AB + AC > BX + XC . 12. Produce AD to X. Then BAC . CDX is greater than Similarly BAD , BDX is greater than CAD ...
... bisector of A meet BC in X ; then AXC is greater than XAB , that is , than △ XAC ; . ' . AC > CX . AB > BX . and .. AB + AC > BX + XC . 12. Produce AD to X. Then BAC . CDX is greater than Similarly BAD , BDX is greater than CAD ...
Strona 6
... bisector of BAC ; OP , OQ perps . on AC , AB ; then △ AOP , AOQ are clearly equal in all respects [ 1. 26 ] ; ... OP = OQ . 4. Here angles at O are equal [ 1. 15 ] ; AXO = BYO , being ; and AO OB ; .. △ AOX , BOY are equal in all ...
... bisector of BAC ; OP , OQ perps . on AC , AB ; then △ AOP , AOQ are clearly equal in all respects [ 1. 26 ] ; ... OP = OQ . 4. Here angles at O are equal [ 1. 15 ] ; AXO = BYO , being ; and AO OB ; .. △ AOX , BOY are equal in all ...
Strona 8
... bisectors be BO , CO ; then BOC = suppt . of sum of OBC , OCB = suppt . of △ ABC . 8 8 8. Let ABCD be the quadril . with at D and C bisected by DO , CO . Then twice the sum of Doc , odc , OCD = 4 rt . " the sum of the four angles of ...
... bisectors be BO , CO ; then BOC = suppt . of sum of OBC , OCB = suppt . of △ ABC . 8 8 8. Let ABCD be the quadril . with at D and C bisected by DO , CO . Then twice the sum of Doc , odc , OCD = 4 rt . " the sum of the four angles of ...
Strona 11
... bisectors of 4 B and C meet at F , and the internal bisectors at E. Then by Ex . 2 , page 29 each of EBF , ECF is a ... bisector of the YPQ meet OY at S. Draw QR perp . to OY and therefore par1 . to PY . Then the AOQR , OQX are equal in ...
... bisectors of 4 B and C meet at F , and the internal bisectors at E. Then by Ex . 2 , page 29 each of EBF , ECF is a ... bisector of the YPQ meet OY at S. Draw QR perp . to OY and therefore par1 . to PY . Then the AOQR , OQX are equal in ...
Strona 16
... bisector of BAC draw OP par1 . to AB , and OQ par1 . to AC . Then QOA = LOAP = LOAQ . .. QO = AQ = OP since OPAQ is a parm . Also OQ = AP ; thus the fig . is equilat . 3. Let D be the pt . of intersection of 16 KEY TO EUCLID .
... bisector of BAC draw OP par1 . to AB , and OQ par1 . to AC . Then QOA = LOAP = LOAQ . .. QO = AQ = OP since OPAQ is a parm . Also OQ = AP ; thus the fig . is equilat . 3. Let D be the pt . of intersection of 16 KEY TO EUCLID .
Inne wydania - Wyświetl wszystko
A Key to the Exercises and Examples Contained in a Text-Book of Euclid's ... H S 1848-1934 Hall Podgląd niedostępny - 2018 |
A Key to the Exercises and Examples Contained in a Text-Book of Euclid's ... H. S. Hall Podgląd niedostępny - 2017 |
Kluczowe wyrazy i wyrażenia
A. W. VERRALL AABC AB² ABCD AC² angles Assistant Master AX² BC² bisector bisects Cambridge centre chord circle circum College concyclic constant describe diam diameter diff draw ELEMENTARY equiangular equilat FASNACHT Fcap fixed point G. E. FASNACHT given base given point given ratio given st GREEK Hence identically equal inscribed intersect Introduction and Notes ISAAC TODHUNTER isosceles Join Let ABC LL.D locus M.A. BOOK meet middle point middle pt orthocentre Owens College par¹ parm pedal triangle perp plane produced Prof Professor Radical Axis radius equal rect respectively segment shewn sides Similarly sum of sqq tangent touch Translated triangle Trinity College vert vols
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