| Robert Gibson - 1795 - Liczba stron: 384
...of the Bafe and Perpendicular, will be the Hypothenufe. Cor. 2. Having .the Hypothenufe and one Leg given to find the other ; the Square Root of the Difference of the Squares of the Hypothenufe and given Leg, will be the required Leg. r HE o. xv. In all Circles the Chord of 60 Degrees... | |
| Robert Gibson - 1806 - Liczba stron: 486
...Calculation. 1. AB : AC + BC : : AC— BC : AD— DB. 2.5 4.3 .3 .516 By cor. 2. theo. 14. sect. 1. The square root of the difference of the squares of the hypothenuse AC, and given leg AD, wtll give DC. ie 5.29—2.274064=3.015936. Its square root is 1.736=CD. • Then... | |
| Robert Gibson - 1808 - Liczba stron: 482
...AC+BC : : AC— BC : AD— DB. 2.5 4.3 .3 .516. 1>25+.258=1.50S=AD. By cftr. 2. theo. 14. sett. 1. The square root of the difference of the squares of the hypothenuse AC, and given leg AD, will give DC. i. e* 5.29—2.274064=3.015936. Its square root is 1.736=CD. Then... | |
| Robert Gibson - 1811 - Liczba stron: 580
...square root of the sum of the squares of the base and perpendicular, will be the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find...the difference of the squares of the hypothenuse and given side, will be the required side. THEO. XV . PL. \.fig. 33. />; all circle* the chord of 60 dt'grtct... | |
| Robert Gibson - 1814 - Liczba stron: 558
...required. By Calculation. 1. AB : AC+BC- - AC—BC: AD—DB. 2.5 4.3 .3 .516. By cor. 2. theo. 14. geom. The square root of the difference of the- squares of the hypothenuse AC, and given leg AD, will give DC. That is, 5.29—2.274064=3.015936. « Its square root is 1.736=... | |
| John Bonnycastle - 1818 - Liczba stron: 488
...square root of the sum of the squares of the other two sides ; and either of the sides is equal to the square root of the difference of the squares of the hypothenuse and the other side. Note, also, that if the half difference of any two quantities be added to their half sum,... | |
| Robert Gibson - 1818 - Liczba stron: 502
...i. AB : AC+BC : : AC— BC : AD— DB,=5l6, Then, 1.25+.258=1.508=AD. By cor. 2. theo. 14. sect. 1. The square root of the difference of the squares of the hypothenuse AC, and .given leg AD, will give DC,=1.736. Then, by the preceding lemma. 2. As CD : AC : : CB : the... | |
| Robert Gibson - 1821 - Liczba stron: 594
...square root of the sum of the squares of the base andperpendiculariwillbe the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find...; the square root of the difference of the squares ofthe hypothenuse and given side, will be the required side. * For different demonstrations of this... | |
| L. Murray - 1821 - Liczba stron: 620
...scaling-ladder. 25 (0) Case 2. If the length of the base, or breadth of the ditch, were required ; then the square root of the difference of" the squares of the hypothenuse and perpendicular is the length of the base, or breadth of the ditch or moat. See the work. 2500 the square... | |
| Michael Walsh - 1831 - Liczba stron: 348
...top of the wall. Ans. 39,05 feet. The hypolhenuse and perpendicular given, to find the base. RULE. The square root of the difference of the squares of the hypothenuse and perpendicular is the length of the base. The base and hypothenuse given, to find the perpendicular.... | |
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