Chemical News and Journal of Industrial Science, Tomy 105-106Chemical news office., 1912 |
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Strona 14
... volume in cc . 0 = A B x absolute temperature . sectional area of tube at A in cm2 . sectional area of tube at B. = distance of mercury surface at в , below platinum- point in mm . filling is secured by the use of a small tube c , which ...
... volume in cc . 0 = A B x absolute temperature . sectional area of tube at A in cm2 . sectional area of tube at B. = distance of mercury surface at в , below platinum- point in mm . filling is secured by the use of a small tube c , which ...
Strona 16
... volume being kept constant by the addition of water . There was thus formed a reddish brown precipitate which after separation and washing was in the form of a brown resinous powder . Extraction of this with boiling petroleum ether ...
... volume being kept constant by the addition of water . There was thus formed a reddish brown precipitate which after separation and washing was in the form of a brown resinous powder . Extraction of this with boiling petroleum ether ...
Strona 18
... volume , the amount of heat evolved would have been different , but the chemical reaction in each case would have ... volume of oxygen at -273 ° C. is 21.21 cc . , of hydrogen 24.18 cc . , and of ice 19.21 cc . Therefore the 16 grms . of ...
... volume , the amount of heat evolved would have been different , but the chemical reaction in each case would have ... volume of oxygen at -273 ° C. is 21.21 cc . , of hydrogen 24.18 cc . , and of ice 19.21 cc . Therefore the 16 grms . of ...
Strona 19
... volume of 24'18 cc . , and at o ° C. it occupied a volume of 22,431 CC . This expansion necessitated the expenditure of work in pushing back the atmosphere . The work so done we will call Ee , and it may be cal culated for 1 grm . from ...
... volume of 24'18 cc . , and at o ° C. it occupied a volume of 22,431 CC . This expansion necessitated the expenditure of work in pushing back the atmosphere . The work so done we will call Ee , and it may be cal culated for 1 grm . from ...
Strona 20
... volume Sp 3/2 R + E + R 5/2 R + E1 Sv 3/2 R + E 3/2 R + E , Now putting in the place of R its value 2/3 = = Energy necessary to overcome external pressure .... Energy necessary to overcome mole- cular attraction .. Energy necessary for ...
... volume Sp 3/2 R + E + R 5/2 R + E1 Sv 3/2 R + E 3/2 R + E , Now putting in the place of R its value 2/3 = = Energy necessary to overcome external pressure .... Energy necessary to overcome mole- cular attraction .. Energy necessary for ...
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