Maud, and Other PoemsEdward Moxon, & Company, Dover Street., 1866 - 170 |
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Strona 1
William ROWLEY (Dramatist.) A Woman never Vext ; OR , THE WIDOW OF CORNHILL . ACT I. SCENE 1. — Hall of Foster's House . FOSTER and BROWN discovered sitting at a table , c . and RICHARD at a desk near R. S. E. examining ac ... Vext; ...
William ROWLEY (Dramatist.) A Woman never Vext ; OR , THE WIDOW OF CORNHILL . ACT I. SCENE 1. — Hall of Foster's House . FOSTER and BROWN discovered sitting at a table , c . and RICHARD at a desk near R. S. E. examining ac ... Vext; ...
Strona 2
... Vext ( r ) . Making use of the relationships Vext ( k ) ñ ( − k ) + 1⁄2 | ñ ( k ) | 2 [ u2 ( k ) + IT ' ( k ) ] Fy ( T ) = F® ( T ) + [ drV « [ ñ ( r ) ] + } [ dr ] & ¥ ñ @ mr_r ] ño + F ? ( T ) and K ( k ) = II - ' ( k ) . The ...
... Vext ( r ) . Making use of the relationships Vext ( k ) ñ ( − k ) + 1⁄2 | ñ ( k ) | 2 [ u2 ( k ) + IT ' ( k ) ] Fy ( T ) = F® ( T ) + [ drV « [ ñ ( r ) ] + } [ dr ] & ¥ ñ @ mr_r ] ño + F ? ( T ) and K ( k ) = II - ' ( k ) . The ...
Strona 9
... vext(r) for N-electron system. Then eq. (1.7) becomes Uext[n] = ∫ n(r)vext(r)dr (1.12) this means that they didn't restrict the external potential vext(r) to be only the classical Coulomb potential as Thomas and Fermi did. Instead ...
... vext(r) for N-electron system. Then eq. (1.7) becomes Uext[n] = ∫ n(r)vext(r)dr (1.12) this means that they didn't restrict the external potential vext(r) to be only the classical Coulomb potential as Thomas and Fermi did. Instead ...
Strona 7
... Vext (r), the potential Vext (r) is determined uniquely, up to an additive constant, by the ground state particle density n0 (r) As Vext (r) is the function of the ground state density n0(r) and Vext (r) fixes the Hamiltonian Eq. (2.3) ...
... Vext (r), the potential Vext (r) is determined uniquely, up to an additive constant, by the ground state particle density n0 (r) As Vext (r) is the function of the ground state density n0(r) and Vext (r) fixes the Hamiltonian Eq. (2.3) ...
Strona 10
... Vext ( r ) – Ve ( r ) + μ ) ) 3/2 ( 2.6 ) Then substitute into the right hand side of eq . ( 2.5 ) to obtain V2Ve ( r ) 4e2 Зпаз ( 2m ( -Vext ( r ) - Ve ( r ) + μ ) ) 3/2 . ( 2.7 ) 2.2.2 . Thomas - Fermi atom Further simplification can ...
... Vext ( r ) – Ve ( r ) + μ ) ) 3/2 ( 2.6 ) Then substitute into the right hand side of eq . ( 2.5 ) to obtain V2Ve ( r ) 4e2 Зпаз ( 2m ( -Vext ( r ) - Ve ( r ) + μ ) ) 3/2 . ( 2.7 ) 2.2.2 . Thomas - Fermi atom Further simplification can ...
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