Breviarium romanum: juxta Conc. Trid1584 |
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... c3 – 3abc ) = - ( a + b + c ) 3 = - ( 4 ) 3 = -64 . ( c ) 2 sin x = 2k +1 + n2 ( ( 1 ) 2 + ( i ) 2 – 21 = 1 1- ( 0 ) ... TU 1 log cos 4 log In di Ind2 In az Now , In a4 In a5 In a6 In an In dg In ag 3 . a b c ( d ) Here , A = a2 b2 C2 [ az bz ...
... c3 – 3abc ) = - ( a + b + c ) 3 = - ( 4 ) 3 = -64 . ( c ) 2 sin x = 2k +1 + n2 ( ( 1 ) 2 + ( i ) 2 – 21 = 1 1- ( 0 ) ... TU 1 log cos 4 log In di Ind2 In az Now , In a4 In a5 In a6 In an In dg In ag 3 . a b c ( d ) Here , A = a2 b2 C2 [ az bz ...
Strona 32
... A6 . At 4/12 = 0.333 and R = 0.05 , X / H2 = 40 and Y / HO = 180. For Ο 。, K , and A unchanged with F = 6 , use ... C3 and C4 , tU // H values of 7 x 102 and 2 x 102 are obtained . Interpolating to F = 4.6 , gives tU / Ho or = 550. Thus ...
... A6 . At 4/12 = 0.333 and R = 0.05 , X / H2 = 40 and Y / HO = 180. For Ο 。, K , and A unchanged with F = 6 , use ... C3 and C4 , tU // H values of 7 x 102 and 2 x 102 are obtained . Interpolating to F = 4.6 , gives tU / Ho or = 550. Thus ...
Strona 36
... c3 a6 6. Bd3 Nc6 7. 0-0 Be7 8. Nbd2 0-0 9. Rel Re8 10. h3 Bd6 11. Bxd6 Qxd6 ... c3 Nf6 4. Bf4 Bf5 5. h3 g6 6. Nbd2 Bg7 7. e3 0-0 8. Nh4 Bd7 9. Bd3 Nh5 10. Nhf3 ... Tu ( Vietnam ) 8 % ; 5th Cindy Tsai ( U.S. ) 8 ; 37th : Anna Levina ( U.S. ) ...
... c3 a6 6. Bd3 Nc6 7. 0-0 Be7 8. Nbd2 0-0 9. Rel Re8 10. h3 Bd6 11. Bxd6 Qxd6 ... c3 Nf6 4. Bf4 Bf5 5. h3 g6 6. Nbd2 Bg7 7. e3 0-0 8. Nh4 Bd7 9. Bd3 Nh5 10. Nhf3 ... Tu ( Vietnam ) 8 % ; 5th Cindy Tsai ( U.S. ) 8 ; 37th : Anna Levina ( U.S. ) ...
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... C3 Đại học Tổng hợp - C4 Vườn Thiên Thanh - Thien D4 National University in Hue Thanh Garden Ga Huế - Hue Railway B4 ... Tu Dam C5 Lăng Dục Đức - Duc Duc Tomb D5 Bến xe Đông Ba - Dong Ba C3 Parking Place Thanh Lịch C4 Thành Nội C3 Pagoda Chùa ...
... C3 Đại học Tổng hợp - C4 Vườn Thiên Thanh - Thien D4 National University in Hue Thanh Garden Ga Huế - Hue Railway B4 ... Tu Dam C5 Lăng Dục Đức - Duc Duc Tomb D5 Bến xe Đông Ba - Dong Ba C3 Parking Place Thanh Lịch C4 Thành Nội C3 Pagoda Chùa ...
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