 | Charles Vyse - 1785 - Liczba stron: 350
...its Diameter is 8000 Miles ? PROBLEM VII. To find the Area of a Circle. RULES. 1 . Multiply Half the the Circumference by Half the Diameter, and the Product will be the Area. Or, 2. Multiply the Square of the Diameter by ,78,54, and' the Product will be the Area. Or, • 3.... | |
 | Peter Nicholson - 1809 - Liczba stron: 426
...the greater segment. PROBLEM XVI. To find the area of a circle, the diameter being given. METHOD I. Multiply half the circumference by half the diameter, and the product will be the area. i EXAMPLE I. What u the area nf a circle lahose diameter is 28 feet, and its circumference 88 feet?... | |
 | Charles Vyse - 1815 - Liczba stron: 340
...perfectly round, and its diameter be 8000 miles? PROBLEM' VIL To find the area of a circle. RULES. ' 1. Multiply half the circumference by half the diameter, and the product will he the area. Or, 2. Multiply the square of the diameter by ,7854, and the product will be the area.... | |
 | Jacob Willetts - 1822 - Liczba stron: 200
...circumference to the diameter ; Or; as 3. 1416 is to 1, so is the circumference to the diameter. III. .Multiply half the circumference by half the diameter and the product will be the area. Or multiply the square of the diameter by. 7854, and the pro* duct will be the area. Or multiply the... | |
 | William Jillard Hort - 1822 - Liczba stron: 308
...opposite angle, and half the product will be the area. Problem. To find the area of a circle. Rule 1. Multiply half the circumference by half the diameter, and the product will be the area. Rule 2. Multiply the square of the diameter by 7854', and the product will be the area. ProUem. To... | |
 | Nicolas Pike - 1822 - Liczba stron: 562
...of the arch line ABC, and by Art. 24, the diameter FB ; then multiply half the chord of the arch ABC by half the diameter, and the product will be the area of the sector ABCE : then find the area of the triangle AEC, wboae base AC is 172, and perpendicular height... | |
 | Anthony Nesbit - 1824 - Liczba stron: 476
...may consult Marrat's Mechanics. Article 768. PROBLEM XV. To find the area of a circle. RULES. _ , 1. Multiply half the circumference by half the diameter, and the product will be the area. Or, divide the product of the whole circumference and diameter by 4t9 and the quotient will be the... | |
 | Peter Nicholson - 1825 - Liczba stron: 1046
...of the greater segment. Prob. 1 6. To find the area of a circle, the diameter being given. Method 1. Multiply half the circumference by half the diameter, and the product will be the area. Ex. l. What is the area of a circle whose diameter is 28 feet, and iU circumference 88 feet ? Method... | |
 | Zadock Thompson - 1826 - Liczba stron: 176
...miles, what is its diameter ? Ans. 79571 nearly. Problem VI. To find the area of a circkj RULE. — Multiply half the circumference by half the diameter, and . the product will be the area. * These three methods do not exactly agree, but the last is the most correct. The exact proportion... | |
 | Martin Ruter - 1828 - Liczba stron: 180
...diameter to the circumference. ARTICLE V. To find the superficial contents, or area, of a circle. RULE. Multiply half the circumference by half the diameter, and the product will be the answer. Or, multiply the square of the diameter by .7854; or multiply the square of the circumference... | |
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Multiply half the circumference by half the diameter, and the product will be the area. Or, divide the product of the whole circumference and diameter -by 4, and the quotient will be the area. 2. Multiply the square of the diameter by .7854, and the product... 
