 | 1801 - Liczba stron: 658
...Or 6 : i :: 28,2744 : 4-7124 Or 3 : 30 :: -05236X9 : 4'7^4 36 4-7124 the answer. RULE a.* . From 8 times the chord of half the arc subtract the chord of the whole arc, and ~ of the remainder "-'ill be the length of the arc nearly. 2. The * DEMONSTRATION. Let the radius OD~r,... | |
 | Thomas Keith - 1817 - Liczba stron: 306
...be the length of the arc. RULE II. From eight times the chord of half the arc, subtract the ^rhord of the whole arc, and onethird of the remainder will be the length of the arc nearly f• Example * When the radius of a circle is i, the semi-circumference is ^•1415926;, Sec. and this... | |
 | Anthony Nesbit, W. Little - 1822 - Liczba stron: 916
...French iaticians, to 128. PROBLEM XII. To Jtnd the length of the arc of a circle. RULE I. By the Pen. 8 times the chord of half the arc subtract the chord of the whole ate, and i of the remainder will be the length of the arc, nearly. Note 1. Half the chord of the whole... | |
 | Anthony Nesbit - 1824 - Liczba stron: 476
...Bonnycastle's As* 'ronomy, page 277. PROBLEM XIV. To find the length of any arc of a circle. RULE I. From 8 times the chord of half the arc subtract the chord of the whole arc, and }, of the remainder . will be the length of the arc, nearly. Kote. Half the chord of the whole arc,... | |
 | John Nicholson - 1825 - Liczba stron: 838
...30 Or 6 : 1 : : 282744 : 47124 Or 3 : 30 : : '05236 X 9 : 47124 90 47124 the answer. Rule 2. From 8 times the chord of half the arc subtract the chord of the whole arc, and ' of the remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prob. 8.) of the whole... | |
 | John Nicholson (Civil engineer) - 1830 - Liczba stron: 240
...: 30 Or 6 : 1 : : 282744 : 47124 Or 3: 30 : : 105236 x 9:47124 90 47124 the answer. Rule 2. From 8 times the chord of half the arc subtract the chord of the whole arc, and .1 of the remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prob. 8.) of the whole... | |
 | Samuel YOUNG (of Manchester.) - 1833 - Liczba stron: 272
...same square whose diameter is 24. PROBLEM IX. To find the length of a Circular Arc. RULE 1. From 8 times the chord of half the arc subtract the chord of the whole arc, and ^ of the difference will be the length of the arc, nearly. RULE 2. Multiply the number of degrees in... | |
 | Francis Walkingame - 1833 - Liczba stron: 204
...5. The area X'6S6G197) Problem 9- Toßnd the length of a circular arc RULE 1. From 8 times Fig. 8. the chord of half the arc subtract the chord of the whole arc, and ¿ of the difference will be the length of the arc, nearly. That is ADx8— AB -т-3=.агс ADB. NOTE.... | |
 | Ireland commissioners of nat. educ - 1834 - Liczba stron: 370
...value of this series, let it be assumed =: d V — ; - т ¿' « — « ^ n\f dv, and we get RULE II. From eight times the chord of half the arc, subtract the chord of the whole arc, and it will be found ^)+ -) = V dv d I X - + « = V* r This being expanded, we get S*^ *cA 8rf2ffT / By... | |
 | William Galbraith - 1834 - Liczba stron: 454
...equivalent to the radius of the circle multiplied by 0.0174533, and by the number of degrees in the arc. Or from eight times the chord of half the arc subtract the chord of the whole arc, one third of this remainder is the length of the arc nearly. 9. Circular Sector.— The area is equivalent... | |
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From eight times the chord of half the arc, subtract the chord of the whole arc, and divide the remainder by 3, and the quotient will be the length of the arc, nearly. 
